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Mastering Quadratic Equations for Class 10 Maths

March 15, 2026

Mastering Quadratic Equations πŸ“˜

Welcome, Class 10 Students! Quadratic Equations is one of the most important chapters in Class 10 Maths. Questions from this topic definitely appear in the CBSE Board exam, often in the form of word problems (applications in daily life), value-based questions, or direct solving questions. If you understand the basic ideas, how to form equations from statements, and how to choose the right method to solve them, you can easily score full marks from this chapter.

πŸ“š 1. Introduction and Core Concepts

A quadratic equation in one variable is an equation that can be written in the standard form:

ax2+bx+c=0ax^2 + bx + c = 0

where:

  • a,b,a, b, and cc are real numbers
  • aβ‰ 0a \neq 0
  • xx is the variable

If a=0a = 0, the equation becomes linear, not quadratic.

Degree of the equation

The highest power of the variable is 2, so it is called a quadratic (degree 2) equation.

Examples of quadratic equations

  • 3x2βˆ’5x+2=03x^2 - 5x + 2 = 0
  • x2βˆ’9=0x^2 - 9 = 0
  • 2x2+7x=02x^2 + 7x = 0

All these can be written in the form ax2+bx+c=0ax^2 + bx + c = 0 with a≠0a \neq 0.

Not quadratic

  • 5x+3=05x + 3 = 0 (degree 1: linear)
  • x3βˆ’4x+1=0x^3 - 4x + 1 = 0 (degree 3: cubic)

Roots / Solutions of a Quadratic Equation

The roots or solutions of a quadratic equation ax2+bx+c=0ax^2 + bx + c = 0 are the values of xx which satisfy the equation (make the LHS zero).

If Ξ±\alpha and Ξ²\beta are the roots of the equation, then:

aΞ±2+bΞ±+c=0andaΞ²2+bΞ²+c=0a\alpha^2 + b\alpha + c = 0 \quad \text{and} \quad a\beta^2 + b\beta + c = 0

Number of roots (solutions) of a quadratic equation: at most 2.


πŸ” 2. Detailed Breakdown & Classifications

Below is a quick view of some important terms related to quadratic equations:

Concept / TermDefinition & Example
Standard formWriting any quadratic equation in the form axΒ² + bx + c = 0
Roots / SolutionsThe values of x that satisfy the equation (make LHS = RHS)
DiscriminantThe expression bΒ² βˆ’ 4ac, which decides the nature of roots
Real and distinct rootsTwo different real solutions of the quadratic equation
Real and equal rootsBoth roots are real and same (repeated root)
No real rootsRoots are non-real (imaginary), not considered at Class 10 level

2.1 Different Methods of Solving Quadratic Equations

At Class 10 level, you need to master three main methods:

  1. Factorisation method
  2. Completing the square method (conceptual, used less in Board questions)
  3. Quadratic formula

(A) Solving by Factorisation

General idea: Convert the quadratic equation to a product of two binomials and use the zero product rule.

Example:

x2βˆ’5x+6=0x^2 - 5x + 6 = 0

Step 1: Split the middle term (βˆ’5x) into two terms whose sum is βˆ’5 and product is 1Γ—6=61 \times 6 = 6.

Numbers are βˆ’2 and βˆ’3.

x2βˆ’2xβˆ’3x+6=0x^2 - 2x - 3x + 6 = 0

Group and factor:

x(xβˆ’2)βˆ’3(xβˆ’2)=0x(x - 2) - 3(x - 2) = 0

Take common factor:

(xβˆ’3)(xβˆ’2)=0(x - 3)(x - 2) = 0

So, either xβˆ’3=0x - 3 = 0 or xβˆ’2=0x - 2 = 0

Thus, x=3x = 3 or x=2x = 2.

These are the roots.

Factorisation works best when the quadratic is easily factorable.


(B) Solving by Completing the Square (Concept)

This method makes a perfect square on one side.

Example:

x2+4xβˆ’5=0x^2 + 4x - 5 = 0

Move constant term:

x2+4x=5x^2 + 4x = 5

Add (42)2=4\left(\frac{4}{2}\right)^2 = 4 to both sides:

x2+4x+4=5+4x^2 + 4x + 4 = 5 + 4

LHS is a perfect square:

(x+2)2=9(x + 2)^2 = 9

Taking square root on both sides:

x+2=Β±3x + 2 = \pm 3

So:

x=βˆ’2+3=1orx=βˆ’2βˆ’3=βˆ’5x = -2 + 3 = 1 \quad \text{or} \quad x = -2 - 3 = -5

This method is the base for deriving the quadratic formula.


(C) Quadratic Formula

For the quadratic equation:

ax2+bx+c=0,a≠0ax^2 + bx + c = 0, \quad a \neq 0

The roots are given by:

x=βˆ’bΒ±b2βˆ’4ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

This is the most powerful method and works for any quadratic equation (even when it is not factorable).


2.2 Discriminant and Nature of Roots

The expression:

D=b2βˆ’4acD = b^2 - 4ac

is called the discriminant.

  1. If D>0D > 0:

    • Two real and distinct roots
  2. If D=0D = 0:

    • Two real and equal roots (repeated root)
  3. If D<0D < 0:

    • No real roots (complex roots – not studied in detail in Class 10)

Example

Consider:

x2βˆ’4x+3=0x^2 - 4x + 3 = 0

Here, a=1,b=βˆ’4,c=3a = 1, b = -4, c = 3

D=b2βˆ’4ac=(βˆ’4)2βˆ’4(1)(3)=16βˆ’12=4>0D = b^2 - 4ac = (-4)^2 - 4(1)(3) = 16 - 12 = 4 > 0

So, roots are real and distinct.


2.3 Sum and Product of Roots

If Ξ±\alpha and Ξ²\beta are roots of ax2+bx+c=0ax^2 + bx + c = 0, then:

Ξ±+Ξ²=βˆ’ba\alpha + \beta = -\frac{b}{a} Ξ±Ξ²=ca\alpha \beta = \frac{c}{a}

These relations are very useful in MCQs and in questions where you need to form a quadratic equation from given roots.

Example

For the equation:

2x2βˆ’5x+3=02x^2 - 5x + 3 = 0

a=2,b=βˆ’5,c=3a = 2, b = -5, c = 3

Sum of roots:

Ξ±+Ξ²=βˆ’ba=βˆ’βˆ’52=52\alpha + \beta = -\frac{b}{a} = -\frac{-5}{2} = \frac{5}{2}

Product of roots:

Ξ±Ξ²=ca=32\alpha \beta = \frac{c}{a} = \frac{3}{2}

βš™οΈ 3. Essential Rules, Formulas, or Mechanisms

Here are the key formulas and results you must remember for CBSE Class 10 exams.

(1) Standard form of a quadratic equation

ax2+bx+c=0,a≠0ax^2 + bx + c = 0, \quad a \neq 0

(2) Quadratic formula

x=βˆ’bΒ±b2βˆ’4ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

(3) Discriminant

D=b2βˆ’4acD = b^2 - 4ac
  • D>0D > 0 β†’ real and distinct roots
  • D=0D = 0 β†’ real and equal roots
  • D<0D < 0 β†’ no real roots

(4) Sum and Product of roots

For roots Ξ±\alpha and Ξ²\beta of ax2+bx+c=0ax^2 + bx + c = 0:

Ξ±+Ξ²=βˆ’ba\alpha + \beta = -\frac{b}{a} Ξ±Ξ²=ca\alpha \beta = \frac{c}{a}

(5) Form of quadratic equation when roots are known

If roots are Ξ±\alpha and Ξ²\beta, then the quadratic equation (with leading coefficient 1) is:

x2βˆ’(Ξ±+Ξ²)x+Ξ±Ξ²=0x^2 - (\alpha + \beta)x + \alpha \beta = 0

More generally (with coefficient kk):

k[x2βˆ’(Ξ±+Ξ²)x+Ξ±Ξ²]=0k\left[x^2 - (\alpha + \beta)x + \alpha \beta\right] = 0

Real-Life Application Example (Very Important for Word Problems)

Problem idea: The product of two consecutive natural numbers is 132. Find the numbers.

Let the first number be nn. Then the next consecutive number is n+1n + 1.

Product condition:

n(n+1)=132n(n + 1) = 132 n2+nβˆ’132=0n^2 + n - 132 = 0

This is a quadratic equation in nn.

Now solve using factorisation or quadratic formula.

Factorising:

We need two numbers whose product is βˆ’132-132 and sum is 11.

Numbers are 1212 and βˆ’11-11.

n2+12nβˆ’11nβˆ’132=0n^2 + 12n - 11n - 132 = 0 n(n+12)βˆ’11(n+12)=0n(n + 12) - 11(n + 12) = 0 (nβˆ’11)(n+12)=0(n - 11)(n + 12) = 0

So, n=11n = 11 or n=βˆ’12n = -12

Since natural numbers are positive, n=11n = 11

Numbers are 11 and 12.


πŸ’‘ Exam-Oriented Pro Tips!

  • Always convert the given statement or equation into standard form axΒ² + bx + c = 0 before choosing a method to solve.
  • In word problems, define your variable clearly (for example, let the speed of the train be x km/h) and write the condition step by step to avoid mistakes.
  • When using the quadratic formula, double-check a, b, c and especially bΒ² βˆ’ 4ac to avoid calculation errors; small sign mistakes are very common.
  • For discriminant-based questions, you often don’t need to find the roots; just compute bΒ² βˆ’ 4ac and compare it with zero.
  • In factorisation, if you can’t quickly find suitable factors, directly switch to the quadratic formula instead of wasting too much time.
  • To remember the quadratic formula, many students use a rhythm: β€œminus b plus-minus root b-square minus 4ac, whole upon 2a”. Repeat it a few times.

πŸ“ 4. Summary & Conclusion

  • A quadratic equation is any equation that can be written in the form ax2+bx+c=0ax^2 + bx + c = 0 with aβ‰ 0a \neq 0.
  • It has at most two roots (solutions).
  • You can solve quadratic equations by:
    • Factorisation
    • Completing the square (mainly for understanding)
    • Quadratic formula

The quadratic formula:

x=βˆ’bΒ±b2βˆ’4ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

is the most general and powerful method.

  • The discriminant D=b2βˆ’4acD = b^2 - 4ac tells you the nature of roots:

    • D>0D > 0: two real and distinct roots
    • D=0D = 0: real and equal roots
    • D<0D < 0: no real roots
  • Sum and product of roots of ax2+bx+c=0ax^2 + bx + c = 0:

    • Sum = βˆ’ba-\dfrac{b}{a}
    • Product = ca\dfrac{c}{a}

These are very useful for:

  • Forming a quadratic equation when roots are given
  • Quick checking and MCQ-type questions

From the exam point of view, focus on:

  • Converting word problems into correct quadratic equations
  • Choosing a suitable solving method
  • Carefully handling signs and arithmetic in the discriminant and quadratic formula

If you practise a variety of problems β€” especially from NCERT textbook and exemplar β€” quadratic equations can easily become a high-scoring chapter for your Class 10 Maths Board exam.


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