Classification of Elements and Periodicity in Properties Set-2

Test your knowledge on Classification of Elements and Periodicity in Properties from Chemistry, Class 11.

50

Minutes

30

Questions

1 / -0

Marking Scheme

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Questions in this Quiz

Q1: How is the covalent radius of a non-metallic element like Chlorine calculated?

  • Half the distance between two atoms when they are bound by a single covalent bond

  • The full internuclear distance between the atoms

  • Half the internuclear distance in a metallic crystal

  • Half the van der Waals radius

Q2: The metallic radius of Copper (Cu\text{Cu}) is assigned a value of 128 pm128\text{ pm}. This is based on the internuclear distance of 256 pm256\text{ pm} between adjacent Cu\text{Cu} atoms in the solid crystal, where the metallic radius is:

  • Twice the internuclear distance

  • Half the internuclear distance

  • Equal to the internuclear distance

  • 256 pm256\text{ pm}

Q3: Why does atomic size generally decrease across a period (left to right)?

  • Effective nuclear charge decreases.

  • The principal quantum number (nn) increases.

  • Effective nuclear charge increases, increasing attraction of electrons to the nucleus within the same valence shell

  • The number of core electrons increases drastically.

Q4: Why does the atomic radius increase as we descend a group?

  • The nuclear charge decreases down the group.

  • The valence electrons are placed farther from the nucleus due to increased principal quantum number (nn) and shielding

  • The electron gain enthalpy becomes more negative.

  • All inner energy levels are completely filled.

Q5: When comparing the size of an anion (X\text{X}^-) to its parent atom (X\text{X}), the anion is:

  • Smaller, due to increased effective nuclear charge

  • Larger, because the added electron increases repulsion and decreases effective nuclear charge

  • Smaller, because it has more protons

  • The same, as the nuclear charge is constant

Q6: An atom (X\text{X}) forms a cation (X+\text{X}^+). Which statement correctly describes the relationship between their sizes?

  • The cation is larger because the remaining electrons are less attracted by the nucleus.

  • The cation is smaller because it has fewer electrons while the nuclear charge remains the same

  • The cation is the same size because only valence electrons are involved.

  • The cation's radius is half the atomic radius.

Q7: Consider the isoelectronic species O2,F,Na+,Mg2+\text{O}^{2-}, \text{F}^{-}, \text{Na}^{+}, \text{Mg}^{2+}. Which ion has the largest radius?

  • Mg2+\text{Mg}^{2+}

  • Na+\text{Na}^{+}

  • F\text{F}^{-}

  • O2\text{O}^{2-} (Anion with greater negative charge has larger radius due to net electron repulsion)

Q8: Which isoelectronic species will have the smallest radius among N3,O2,F\text{N}^{3-}, \text{O}^{2-}, \text{F}^{-}?

  • N3\text{N}^{3-}

  • O2\text{O}^{2-}

  • F\text{F}^{-}

  • All are the same size

Q9: Arrange the following isoelectronic species in the order of increasing ionic radii: Mg2+,Na+,F\text{Mg}^{2+}, \text{Na}^{+}, \text{F}^{-}.

  • Mg2+<Na+<F\text{Mg}^{2+} < \text{Na}^{+} < \text{F}^{-}

  • F<Na+<Mg2+\text{F}^{-} < \text{Na}^{+} < \text{Mg}^{2+}

  • Na+<Mg2+<F\text{Na}^{+} < \text{Mg}^{2+} < \text{F}^{-}

  • Mg2+<F<Na+\text{Mg}^{2+} < \text{F}^{-} < \text{Na}^{+}

Q10: Why are the atomic radii of noble gases not typically compared with the covalent radii of other elements?

  • They are monoatomic, and their non-bonded (van der Waals) radii values are typically very large

  • They are highly reactive.

  • Their atomic numbers are too high.

  • They are located in the pp-block.

...and 20 more questions.