Classification of Elements and Periodicity in Properties Set-2
Test your knowledge on Classification of Elements and Periodicity in Properties from Chemistry, Class 11.
50
Minutes
30
Questions
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Questions in this Quiz
Q1: How is the covalent radius of a non-metallic element like Chlorine calculated?
- Half the distance between two atoms when they are bound by a single covalent bond
- The full internuclear distance between the atoms
- Half the internuclear distance in a metallic crystal
- Half the van der Waals radius
Q2: The metallic radius of Copper ($\text{Cu}$) is assigned a value of $128\text{ pm}$. This is based on the internuclear distance of $256\text{ pm}$ between adjacent $\text{Cu}$ atoms in the solid crystal, where the metallic radius is:
- Twice the internuclear distance
- Half the internuclear distance
- Equal to the internuclear distance
- $256\text{ pm}$
Q3: Why does atomic size generally decrease across a period (left to right)?
- Effective nuclear charge decreases.
- The principal quantum number ($n$) increases.
- Effective nuclear charge increases, increasing attraction of electrons to the nucleus within the same valence shell
- The number of core electrons increases drastically.
Q4: Why does the atomic radius increase as we descend a group?
- The nuclear charge decreases down the group.
- The valence electrons are placed farther from the nucleus due to increased principal quantum number ($n$) and shielding
- The electron gain enthalpy becomes more negative.
- All inner energy levels are completely filled.
Q5: When comparing the size of an anion ($\text{X}^-$) to its parent atom ($\text{X}$), the anion is:
- Smaller, due to increased effective nuclear charge
- Larger, because the added electron increases repulsion and decreases effective nuclear charge
- Smaller, because it has more protons
- The same, as the nuclear charge is constant
Q6: An atom ($\text{X}$) forms a cation ($\text{X}^+$). Which statement correctly describes the relationship between their sizes?
- The cation is larger because the remaining electrons are less attracted by the nucleus.
- The cation is smaller because it has fewer electrons while the nuclear charge remains the same
- The cation is the same size because only valence electrons are involved.
- The cation's radius is half the atomic radius.
Q7: Consider the isoelectronic species $\text{O}^{2-}, \text{F}^{-}, \text{Na}^{+}, \text{Mg}^{2+}$. Which ion has the largest radius?
- $\text{Mg}^{2+}$
- $\text{Na}^{+}$
- $\text{F}^{-}$
- $\text{O}^{2-}$ (Anion with greater negative charge has larger radius due to net electron repulsion)
Q8: Which isoelectronic species will have the smallest radius among $\text{N}^{3-}, \text{O}^{2-}, \text{F}^{-}$?
- $\text{N}^{3-}$
- $\text{O}^{2-}$
- $\text{F}^{-}$
- All are the same size
Q9: Arrange the following isoelectronic species in the order of increasing ionic radii: $\text{Mg}^{2+}, \text{Na}^{+}, \text{F}^{-}$.
- $\text{Mg}^{2+} < \text{Na}^{+} < \text{F}^{-}$
- $\text{F}^{-} < \text{Na}^{+} < \text{Mg}^{2+}$
- $\text{Na}^{+} < \text{Mg}^{2+} < \text{F}^{-}$
- $\text{Mg}^{2+} < \text{F}^{-} < \text{Na}^{+}$
Q10: Why are the atomic radii of noble gases not typically compared with the covalent radii of other elements?
- They are monoatomic, and their non-bonded (van der Waals) radii values are typically very large
- They are highly reactive.
- Their atomic numbers are too high.
- They are located in the $p$-block.
Q11: In the sequence $\text{Mg}, \text{Mg}^{2+}, \text{Al}, \text{Al}^{3+}$, identify the species with the largest size.
- $\text{Mg}$ (Largest parent atom)
- $\text{Mg}^{2+}$
- $\text{Al}$
- $\text{Al}^{3+}$
Q12: The ionic radius of Fluoride ion ($\text{F}^{-}$) is $136\text{ pm}$, while the atomic radius of Fluorine ($\text{F}$) is $64\text{ pm}$. This drastic increase in size is primarily due to:
- Decrease in nuclear charge
- Increased electron-electron repulsion and decrease in effective nuclear charge
- The loss of the valence shell
- The electron entering the $n=3$ quantum level
Q13: Which of the following elements, $\text{Li}, \text{Na}, \text{K}, \text{Rb}, \text{Cs}$, has the largest atomic radius?
- $\text{Rb}$
- $\text{K}$
- $\text{Cs}$
- $\text{Li}$
Q14: Considering elements $\text{Na, Mg, Al, Si, P, S, Cl}$ (Period 3), which element has the smallest atomic radius?
- $\text{Na}$
- $\text{Si}$
- $\text{Cl}$
- $\text{Mg}$
Q15: The species $\text{Ar}, \text{K}^{+}, \text{Ca}^{2+}$ are isoelectronic. The correct order of their radii (from smallest to largest) is:
- $\text{Ar} < \text{K}^{+} < \text{Ca}^{2+}$
- $\text{Ca}^{2+} < \text{K}^{+} < \text{Ar}$
- $\text{K}^{+} < \text{Ar} < \text{Ca}^{2+}$
- $\text{Ar} < \text{Ca}^{2+} < \text{K}^{+}$
Q16: Ionization Enthalpy ($\Delta_i H$) is the energy required to remove an electron from an atom in which specific state?
- Isolated gaseous atom in its ground state
- Liquid atom
- Solid crystal lattice
- Gaseous ion in an excited state
Q17: The second ionization enthalpy ($\Delta_i H_2$) is always higher than the first ionization enthalpy ($\Delta_i H_1$) because:
- It is easier to remove an electron from a positively charged ion than from a neutral atom.
- Energy is always required to remove electrons from an atom.
- It is more difficult to remove an electron from a positively charged ion than from a neutral atom
- Effective nuclear charge decreases after the first removal.
Q18: On a plot of first ionization enthalpies ($\Delta_i H$) versus atomic number ($Z$), where do the maxima (highest values) occur?
- At the noble gases
- At the alkali metals
- At the halogens
- At the alkaline earth metals
Q19: Why does ionization enthalpy generally increase across a period?
- Increase in shielding outweighs the increase in nuclear charge.
- Successive electrons are added to orbitals in the same principal quantum level, and increasing nuclear charge outweighs shielding
- The valence electrons are increasingly farther from the nucleus.
- The principal quantum number ($n$) decreases.
Q20: The first ionization enthalpy of Boron ($\text{Z}=5$) is slightly less than that of Beryllium ($\text{Z}=4$) because:
- The $2s$ electron in $\text{Be}$ is more shielded than the $2p$ electron in $\text{B}$.
- The $2p$ electron in $\text{B}$ is more shielded by inner core electrons than the $2s$ electron in $\text{Be}$, making it easier to remove
- $\text{Be}$ has a higher atomic number.
- $\text{B}$ has a completely filled $2s$ orbital.
Q21: The "anomaly" of Oxygen ($\text{O}$) having a smaller first ionization enthalpy than Nitrogen ($\text{N}$) arises because:
- Oxygen has a lower nuclear charge.
- Oxygen has increased electron-electron repulsion due to paired electrons in a $2p$-orbital, making removal easier
- Nitrogen has a completely filled $2p$ subshell.
- Oxygen is more electronegative than Nitrogen.
Q22: The first ionization enthalpy values for $\text{Na}, \text{Mg}$, and $\text{Si}$ are $496, 737$, and $786\text{ kJ mol}^{-1}$ respectively. Based on shielding and orbital configuration, the first $\Delta_i H$ value for $\text{Al}$ should be closest to: (Hard Level)
- $760\text{ kJ mol}^{-1}$
- $575\text{ kJ mol}^{-1}$ (Lower than $\text{Mg}$ due to effective shielding of $3p$ electron by $3s$ electrons)
- $490\text{ kJ mol}^{-1}$
- $737\text{ kJ mol}^{-1}$
Q23: For an element with the electronic configuration $\text{1s}^2 \text{2s}^2 \text{2p}^6 \text{3s}^1$, which ionization enthalpy will show a significantly large jump in value?
- $\Delta_i H_1$
- $\Delta_i H_2$ (Removal breaks into the stable noble gas core, $[\text{Ne}]$)
- $\Delta_i H_3$
- $\Delta_i H_4$
Q24: The valence electron in Lithium ($\text{Li}$) is shielded from the nucleus by the inner core of $1s$ electrons. The reduction in the effective nuclear charge experienced by this valence electron is known as:
- Electronegativity
- Ionization Potential
- Shielding or Screening
- Penetration Effect
Q25: The ionization enthalpies generally decrease down a group primarily because:
- Effective nuclear charge increases significantly.
- The outermost electron is increasingly farther from the nucleus, and increased shielding outweighs the increasing nuclear charge
- The atomic radius decreases.
- The number of valence electrons increases.
Q26: An element $\text{I}$ has $\Delta_i H_1 = 520\text{ kJ mol}^{-1}$ and a very high $\Delta_i H_2 = 7300\text{ kJ mol}^{-1}$. Which statement is true about element $\text{I}$?
- It is the least reactive element.
- It is an Alkali Metal (Group 1)
- It forms a stable binary halide $\text{MX}_2$.
- It is a Noble Gas.
Q27: An element $\text{VI}$ has $\Delta_i H_1 = 738\text{ kJ mol}^{-1}$ and $\Delta_i H_2 = 1451\text{ kJ mol}^{-1}$. This small difference between $\Delta_i H_1$ and $\Delta_i H_2$ suggests that element $\text{VI}$ is likely to be:
- A noble gas
- An alkali metal
- An alkaline earth metal (forms stable $\text{M}^{2+}$ ion)
- A halogen
Q28: What is the correct order of the first ionization enthalpy for the second period elements $\text{Li, Be, B}$?
- $\text{Li} < \text{Be} < \text{B}$
- $\text{Li} < \text{B} < \text{Be}$
- $\text{B} < \text{Be} < \text{Li}$
- $\text{Be} < \text{B} < \text{Li}$
Q29: When considering the elements $\text{B, Al, Mg,}$ and $\text{K}$, what is the correct order of their metallic character (from least metallic to most metallic)?
- $\text{B} < \text{Al} < \text{Mg} < \text{K}$
- $\text{K} < \text{Mg} < \text{Al} < \text{B}$
- $\text{B} < \text{Mg} < \text{Al} < \text{K}$
- $\text{Al} < \text{B} < \text{Mg} < \text{K}$
Q30: Which statement regarding ionization enthalpy is incorrect?
- The removal of an electron from orbitals bearing lower $n$ value is easier than from an orbital having higher $n$ value
- Ionization enthalpy increases for each successive electron removed.
- A big jump in ionization enthalpy marks the end of valence electrons.
- The greatest increase in ionization enthalpy occurs upon removal of an electron from the core noble gas configuration.