Some Basic Concepts of Chemistry Set-2

Test your knowledge on Some Basic Concepts of Chemistry from Chemistry, Class 11.

50

Minutes

30

Questions

1 / -0

Marking Scheme

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Questions in this Quiz

Q1: If the moles of the solute are cancelled out by the total number of moles, the resulting quantity is:

  • Molality

  • Molarity

  • Mole fraction

  • Percentage by volume

Q2: What is the standard SI\text{SI} unit of time?

  • Minute

  • Hour

  • Second

  • Day

Q3: Which law states that equal volumes of gases at the same temperature and pressure should contain equal number of molecules?

  • Law of definite proportions

  • Law of multiple proportions

  • Law of conservation of mass

  • Avogadro law

Q4: How many moles of water are present in 180 grams of water (H2O)180\text{ grams of water } (\text{H}_2\text{O})?

  • 5 mol5\text{ mol}

  • 1 mol1\text{ mol}

  • 10 mol10\text{ mol}

  • 18 mol18\text{ mol}

Q5: How many molecules are present in 10 moles of water10\text{ moles of water}?

  • 6.023×10236.023 \times 10^{23} molecules

  • 6.023×10246.023 \times 10^{24} molecules

  • 1010 molecules

  • 10×6.022×102310 \times 6.022 \times 10^{23} atoms

Q6: If a solution contains 10g of NaOH10\text{g of } \text{NaOH} (Molar Mass =40 g/mol= 40\text{ g/mol}) dissolved in 100g of water100\text{g of water}, what is the number of moles of NaOH\text{NaOH}?

  • 0.25 mol0.25\text{ mol}

  • 0.1 mol0.1\text{ mol}

  • 0.5 mol0.5\text{ mol}

  • 1 mol1\text{ mol}

Q7: If the molality of an aqueous solution is 1m1\text{m}, what is the mass of the solvent (water)?

  • 1 L1\text{ L}

  • 100 g100\text{ g}

  • 1000 g1000\text{ g}

  • 10 g10\text{ g}

Q8: The volume of pure water required to have a mass of 1000 grams1000\text{ grams} is: (Density 1 g/mL1\text{ g/mL})

  • 100 mL100\text{ mL}

  • 1000 mL1000\text{ mL}

  • 1 L1\text{ L}

  • Both (2) and (3)

Q9: The relationship used when mixing two solutions (A and B) of the same substance to find the final molarity (MFM_F) and final volume (VFV_F) is:

  • M1V1+M2V2=MF/VFM_1V_1 + M_2V_2 = M_F / V_F

  • M1V1/M2V2=MF/VFM_1V_1 / M_2V_2 = M_F / V_F

  • M1V1+M2V2=MFVFM_1V_1 + M_2V_2 = M_F V_F

  • M1V1M2V2=MFVFM_1V_1 - M_2V_2 = M_F V_F

Q10: What is the molar mass of Copper Sulphate (CuSO4)(\text{CuSO}_4)? (Atomic weight Cu=63.5, S=32, O=16\text{Cu} = 63.5, \text{ S} = 32, \text{ O} = 16)

  • 159.5 g/mol159.5\text{ g/mol}

  • 120 g/mol120\text{ g/mol}

  • 95.5 g/mol95.5\text{ g/mol}

  • 180 g/mol180\text{ g/mol}

...and 20 more questions.