Electric Charges and Fields Set-1

Test your knowledge on Electric Charges and Fields from Physics, Class 12.

60

Minutes

30

Questions

1 / -0

Marking Scheme

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Questions in this Quiz

Q1: . Two point charges placed in a medium of dielectric constant 5 are at a distance rr between them, experience an electrostatic force 'F'. The electrostatic force between them in vacuum at the same distance rr will be:

  • 5F5F

  • FF

  • F/2F/2

  • F/5F/5

Q2: In an experiment three microscopic latex spheres are sprayed into a chamber and became charged with charges +3e+3e, +5e+5e and 3e-3e respectively. All the three spheres came in contact simultaneously for a moment and got separated. Which one of the following are possible values for the final charge on the spheres?

  • +5e+5e, 1e-1e, +5e+5e

  • +6e+6e, +6e+6e, 7e-7e

  • 4e-4e, +3.5e+3.5e, +5.5e+5.5e

  • +5e+5e, 8e-8e, +7e+7e

Q3: Two point charges +8q+8q and 2q-2q are located at x=0x=0 and x=Lx=L respectively. The point on xx-axis at which net electric field is zero due to these charges is:

  • 8L8L

  • 4L4L

  • 2L2L

  • LL

Q4: The electric potential VV at any point (x,y,z)(x, y, z) is given by V=3x2V = 3x^2 where xx is in metres and VV in volts. The electric field at the point (1m,0.2m)(1\text{m}, 0.2\text{m}) is:

  • 6 V/m6 \text{ V/m} along (x)(-\text{x})-axis

  • 6 V/m6 \text{ V/m} along (+x)(+\text{x})-axis

  • 1.5 V/m1.5 \text{ V/m} along (x)(-\text{x})-axis

  • 1.5 V/m1.5 \text{ V/m} along (+x)(+\text{x})-axis

Q5: Assertion (A): On going away from a point charge or a small electric dipole, electric field decreases at the same rate in both the cases.
Reason (R): Electric field is inversely proportional to square of distance from the charge or an electric dipole.

  • Both A and R are true and R is the correct explanation of A.

  • Both A and R are true but R is NOT the correct explanation of A.

  • A is true but R is false.

  • A is false and R is also false.

Q6: The electric field at r=Rr = R (for a non-uniformly distributed nuclear charge ZeZ e within nucleus radius RR) is:

  • directly proportional to aa

  • directly proportional to a2a^2

  • inversely proportional to aa

  • independent of aa

Q7: The electric field within the nucleus is generally observed to be linearly dependent on rr. This implies:

  • a=0a = 0

  • a=R/2a = R/2

  • a=Ra = R

  • a=2R/3a = 2R/3

Q8: Electric field intensity at point PP due to charge distributed over a sphere is:

  • E=14πϵ0qr2E = \frac{1}{4\pi \epsilon_0} \frac{q}{r^2}

  • E=σR2ϵ02r2E = \frac{\sigma R^2}{\epsilon_0 2r^2}

  • E=14πϵ02qr2E = \frac{1}{4\pi \epsilon_0} \frac{2q}{r^2}

  • E=0E = 0

Q9: When point PP is inside a conducting spherical shell:

  • E=0E = 0

  • E=14πϵ0qr2E = \frac{1}{4\pi \epsilon_0} \frac{q}{r^2}

  • cannot be calculated

  • remains constant everywhere inside the sphere (always non-zero)

Q10: Which statement is true for Gauss's law:

  • All the charges whether inside or outside the gaussian surface contribute to the electric flux.

  • Electric flux depends upon the geometry of the gaussian surface.

  • Gauss's theorem can be applied to non-uniform electric field.

  • The electric field over the Gaussian surface remains continuous and uniform at every point.

...and 20 more questions.