Electric charges and fields form the bedrock of electrostatics; understanding how Coulomb's law, superposition and Gauss's law link charge distributions to fields and potentials is crucial for solving both board-level numerical problems and competitive-exam conceptual tasks. Mastery of this chapter enables identification of symmetry, choice of Gaussian surfaces, and correct application of approximations — skills that repeatedly appear in CBSE board, JEE Main and NEET questions.
Beyond rote formulas, exams test reasoning: predicting induced charges on conductors, interpreting field/potential graphs, and combining calculus with physical insight. The following set of 10 carefully chosen MCQs emphasizes multi-step reasoning, graph/data interpretation, assertion–reason logic and numerical calculation typical of CBSE/JEE/NEET level problems.
15
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10
Questions
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Marking Scheme
Q1. (Two point charges and are fixed on the ‑axis at and respectively. Let be a point on the line joining them where the net electric field is zero. The coordinate of measured from the charge is closest to:)
Q2. (Assertion (A): For an isolated metallic conductor in electrostatic equilibrium all excess charge resides entirely on its outer surface.
Reason (R): The electric field at points outside a uniformly charged spherical shell is identical to that produced by a point charge placed at its centre.)
Q3. (A solid insulating sphere of total charge and radius has charge distributed uniformly throughout its volume. Using the known behaviour for and for , the ratio equals:)
Q4. (A neutral hollow conducting spherical shell initially isolated has a point charge placed at the geometric centre of its cavity. The shell is then connected to earth (grounded) and after electrostatic equilibrium is reached the ground connection is removed while the point charge remains inside. The net charge on the conductor and the electric field outside the shell respectively are:)
Q5. (Assertion (A): In electrostatic equilibrium the electric field inside the bulk of a conductor is zero.
Reason (R): Hence the electric potential everywhere inside the conductor must be zero.)
Q6. A spherically symmetric charge distribution produces an electric field of magnitude
where . The electric potential at the centre relative to infinity, , equals:
Q7. (A dipole consists of charges at and at (so dipole moment ) and is centered at the origin along the ‑axis. It is placed in an external electric field (with constant). To first order in the net force on the dipole is:)
Q8. (Assertion (A): If the total charge enclosed by a Gaussian surface is zero, then the electric field must be zero everywhere on that surface.
Reason (R): Gauss's law states that the net flux through a closed surface equals the enclosed charge divided by .)
Q9. (A point charge is held at a distance above an infinite grounded conducting plane in vacuum. Using the method of images, the magnitude of the electrostatic force on is approximately:)
Q10. (A ring of radius carries total charge uniformly distributed. The axial field at a distance from the centre is
For the value of at which is maximum is:)