Motion in a Plane Set-2

Test your knowledge on Motion in a Plane from Physics, Class JEE.

60

Minutes

30

Questions

4 / -1

Marking Scheme

Don't have an account? Sign up for free to save your progress and track your history.

Questions in this Quiz

Q1: The position vector of a particle changes with time according to the relation r(t)=15t2i^+(420t2)j^\vec{r}(t) = 15t^2 \hat{i} + (4 - 20t^2)\hat{j}. What is the magnitude of the acceleration at t=1t = 1?

  • 4040

  • 2525

  • 100100

  • 5050

Q2: A particle moves from the point (2.0i^+4.0j^)m(2.0\hat{i} + 4.0\hat{j}) m, at t=0t = 0, with an initial velocity (5.0i^+4.0j^)ms1(5.0\hat{i} + 4.0\hat{j}) \text{ms}^{-1}. It is acted upon by a constant force which produces a constant acceleration (4.0i^+4.0j^)ms2(4.0\hat{i} + 4.0\hat{j}) \text{ms}^{-2}. What is the distance of the particle from the origin at time 2s2s?

  • 15m15 m

  • 202m20\sqrt{2} m

  • 5m5 m

  • 102m10\sqrt{2} m

Q3: A particle is moving along the xx-axis with its coordinate with time ‘tt’ given by x(t)=10+8t3t2x(t) = 10 + 8t - 3t^2. Another particle is moving along the yy-axis with its coordinate as function of time given by y(t)=58t3y(t) = 5 - 8t^3. At t=1st = 1 s, the speed of the second particle as measured in the frame of the first particle is given as v\sqrt{v}. Then vv (in m/s\text{m/s}) is ______.

Q4: The trajectory of a projectile near the surface of the earth is given as y=2x9x2y = 2x - 9x^2. If it were launched at an angle θ0\theta_0 with speed v0v_0 then (g=10ms2g = 10 \text{ms}^{-2})

  • θ0=sin115\theta_0 = \sin^{-1} \frac{1}{\sqrt{5}} and v0=53ms1v_0 = \frac{5}{3} \text{ms}^{-1}

  • θ0=cos1(25)\theta_0 = \cos^{-1} \left(\frac{2}{\sqrt{5}}\right) and v0=35ms1v_0 = \frac{3}{5} \text{ms}^{-1}

  • θ0=cos1(15)\theta_0 = \cos^{-1} \left(\frac{1}{\sqrt{5}}\right) and v0=53ms1v_0 = \frac{5}{3} \text{ms}^{-1}

  • θ0=sin1(25)\theta_0 = \sin^{-1} \left(\frac{2}{\sqrt{5}}\right) and v0=35ms1v_0 = \frac{3}{5} \text{ms}^{-1}

Q5: Two guns A and B can fire bullets at speed 1km/s1 \text{km/s} and 2km/s2 \text{km/s} respectively. From a point on a horizontal ground, they are fired in all possible directions. The ratio of maximum areas covered by the bullets fired by the two guns, on the ground is:

  • 1:161:16

  • 1:21:2

  • 1:41:4

  • 1:81:8

Q6: The position of a projectile launched from the origin at t=0t = 0 is given by r=(40i^+50j^)m\vec{r} = (40\hat{i} + 50\hat{j}) m at t=2st = 2s. If the projectile was launched at an angle θ\theta from the horizontal, then θ\theta is (take g=10ms2g = 10 \text{ms}^{-2})

  • tan123\tan^{-1} \frac{2}{3}

  • tan132\tan^{-1} \frac{3}{2}

  • tan174\tan^{-1} \frac{7}{4}

  • tan145\tan^{-1} \frac{4}{5}

Q7: A projectile is given an initial velocity of (i^+2j^)m/s(\hat{i} + 2\hat{j}) \text{m/s}, where i^\hat{i} is along the ground and j^\hat{j} is along the vertical. If g=10m/s2g = 10 \text{m/s}^2, the equation of its trajectory is

  • y=x5x2y = x - 5x^2

  • y=2x5x2y = 2x - 5x^2

  • 4y=2x5x24y = 2x - 5x^2

  • 4y=2x25x24y = 2x - 25x^2

Q8: A ball projected from ground at an angle of 4545^\circ just clears a wall in front. If point of projection is 4m4 m from the foot of wall and ball strikes the ground at a distance of 6m6 m on the other side of the wall, the height of the wall is:

  • 4.4m4.4 m

  • 2.4m2.4 m

  • 3.6m3.6 m

  • 1.6m1.6 m

Q9: The stream of a river is flowing with a speed of 2km/h2 \text{km/h}. A swimmer can swim at a speed of 4km/h4 \text{km/h}. What should be the direction of the swimmer with respect to the flow of the river to cross the river straight?

  • 9090^\circ

  • 150150^\circ

  • 120120^\circ

  • 6060^\circ

Q10: A particle is moving along a circular path with a constant speed of 10ms110 \text{ms}^{-1}. What is the magnitude of the change in velocity of the particle, when it moves through an angle of 6060^\circ around the center of circle?

  • 103m/s10\sqrt{3} \text{m/s}

  • zero

  • 102m/s10\sqrt{2} \text{m/s}

  • 10m/s10 \text{m/s}

...and 20 more questions.