Unit And Dimensions Set-3

Test your knowledge on Unit And Dimensions from Physics, Class JEE.

60

Minutes

30

Questions

4 / -1

Marking Scheme

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Questions in this Quiz

Q1: In a book, the answer for a particular question is expressed as b=mak[1+2klma]b = \frac{m a}{k} \left[ \sqrt{1 + \frac{2 k l}{m a}} \right] here mm represents mass, aa represents acceleration, ll represents length. The unit of bb should be

  • m/sm/s

  • m/s2m/s^2

  • meter

  • /sec/sec

Q2: A simple pendulum is being used to determine the value of gravitational acceleration gg at a certain place. The length of the pendulum is 25.0 cm and a stop watch of 1s resolution measures the time taken for 40 oscillations to be 50 s. The accuracy in gg is:

  • 4.40%

  • 3.40%

  • 2.40%

  • 5.40%

Q3: In a simple pendulum experiment for determination of acceleration due to gravity (gg), time taken for 20 oscillations is measured by using a watch of 1 second least count. The mean value of time taken comes out to be 30 s. The length of pendulum is measured by using a meter scale of least count 1 mm and the value obtained 55.0 cm. The percentage error in the determination of gg is close to

  • 0.7%

  • 6.8%

  • 3.5%

  • 0.2%

Q4: The least count of the main scale of a screw gauge is 1 mm. The minimum number of divisions on its circular scale required to measure 5 μm diameter of a wire is

  • 50

  • 200

  • 500

  • 100

Q5: The pitch and the number of divisions, on the circular scale for a given screw gauge are 0.5 mm and 100, respectively. When the screw gauge is fully tightened without any object, the zero of its circular scale lies 3 divisions below the mean line. The readings of the main scale and the circular scale for a thin sheet are 5.5 mm and 48 respectively, the thickness of this sheet is

  • 5.950 mm

  • 5.725 mm

  • 5.755 mm

  • 5.740 mm

Q6: A screw gauge with a pitch of 0.5 mm and a circular scale with 50 divisions is used to measure the thickness of a thin sheet of aluminium. Before starting the measurement, it is found that when the two jaws of the screw gauge are brought in contact, the 45th division coincides with the main scale line and that the zero of the main scale is barely visible. What is the thickness of the sheet, if the main scale reading is 0.5 mm and the 25th division coincides with the main scale line?

  • 0.75 mm

  • 0.80 mm

  • 0.70 mm

  • 0.50 mm

Q7: There are two vernier calipers both of which have 1 cm divided into 10 equal divisions on the main scale. The vernier scale of one of the calipers (C1C_1) has 10 equal divisions that correspond to 9 main scale divisions. The vernier scale of the other caliper (C2C_2) has 10 equal divisions that correspond to 11 main scale divisions. The readings of the two calipers are shown in the figure. The measured values (in cm) by calipers C1C_1 and C2C_2 respectively, are

  • 2.87 and 2.87

  • 2.87 and 2.83

  • 2.85 and 2.82

  • 2.87 and 2.86

Q8: A student measured the length of a rod and wrote it as 3.50 cm. Which instrument did he use to measure it?

  • A meter scale

  • A vernier caliper where the 10 divisions in vernier scale matches with 9 divisions in main scale and main scale has 10 divisions in 1 cm

  • A screw gauge having 100 divisions in the circular scale and pitch as 1 mm.

  • A screw gauge having 50 divisions in the circular scale

Q9: The diameter of a cylinder is measured using a vernier calipers with no zero error. It is found that the zero of the vernier scale lies between 5.10 cm and 5.15 cm of the main scale. The vernier scale has 50 division equivalent to 2.45 cm. The 24th division of the vernier scale exactly coincides with one of the main scale divisions. The diameter of the cylinder is

  • 5.112 cm

  • 5.124 cm

  • 5.136 cm

  • 5.148 cm

Q10: In the determination of Young's modulus 4MLgπd2l\frac{4MLg}{\pi d^2 l} by using Searle's method, a wire of length L=2L = 2 m and diameter d=0.5d = 0.5 mm is used. For a load M=2.5M = 2.5 kg, an extension l=0.25l = 0.25 mm in the length of the wire is observed. Quantities dd and ll are measured using a screw gauge and a micrometer, respectively. They have the same pitch of 0.5 mm. The number of divisions on their circular scale is 100. The contributions to the maximum probable error of the Y measurement is

  • due to the errors in the measurements of dd and ll are the same

  • due to the error in the measurement of dd is twice that due to the error in the measurement of ll

  • due to the error in the measurement of ll is twice that due to the error in the measurement of dd

  • due to the error in the measurement of dd is four times that due to the error in the measurement of ll

...and 20 more questions.